The second step is easy, but Iβm not sure how to do the first one.. another way would be to just findMany and update them individually, but I think it would be much faster if I could solve it in one query?
r
Ryan
06/08/2021, 12:26 PM
@Nichita Z π
Unfortunately the 1st isnβt possible at the moment. It would be great if you could add a π on this request so that we can look at the priority π
The workaround would be a raw query via