When I try to set a default to to a timestamp I always get an error:

DateTime?                @db.Timestamp(6)

hey Jonathan, the best approach I've found is to use

graphql-scalars

and

@types/graphql-scalars

in your entity/object defs for your models so for phoneNumber, for example, I use

PhoneNumberResolver

which throws an error if a phone number field doesn't conform to the international standard E144 format (basically just a "+"-sign with the countrycode before a phone number) so

<tel:+18885551234|+18885551234>

would be accepted, but

18885551234

would throw an error it resolves to a

PhoneNumberScalar

type in the schema same thing applies to ISO-8601 International Time format--I believe it is called a

TimeResolver

in the graphql-scalars package a hacky workaround for getting ISO-8601 starting with a full datetime string would be

const getTimestamp = new Date(Date.now()).toISOString();
console.log(getTimestamp)

const getDateOnly = getTimestamp.split(/([T])/)[0];

// the "T" character is at index 1 of this split datetime string
// "2022-02-09T23:13:22.620Z": [0] 2022-02-09 | [1] T | [2] 23:13:22.620Z

const getTimeOnly = getTimestamp.split(/([T])/)[2];

console.log(JSON.stringify({
  isoDate: getDateOnly,
  isoTime: getTimeOnly
}, null, 2))

// don't want the TZ appended on the end? 
const removeTrailingTZCharacter = getTimeOnly.split(/([Z])/)[0];
// outputs [0] 23:13:22.620 (the Z is at index 1)
console.log(removeTrailingTZCharacter);

ok thanks, we aren’t using graphql I will try the

@db.generated("")