what if i write two generate_repy method together ...
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c
what if i write two generate_repy method together example
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await session.generate_reply("greet the user")
generate_reply("tell a joke to the user")
then will the agent execute the second generate reply instruction after the agent has said its full sentence for the first generate_reply call. or will it execute without waiting. or will it only wait till the generate_reply generates the message using llm and not wait for agent to fully complete saying it. what will happen here
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t
Thanks for reaching out, Kushagra. I'm an AI assistant and I'm here to help. Give me a moment while I research this topic.
Thanks — I’m answering your question about what happens when you call
generate_reply
twice. • If you
await
the first call (your example), the first reply will finish fully before the next call runs: a. LLM generates the first message b. the agent speaks the full first reply c. then the second
generate_reply()
executes • If you call both without
await
, they run concurrently and can overlap (generation and/or playback may interleave). • For finer control use the returned `SpeechHandle`: ◦
handle = session.generate_reply(...)
◦
await handle.wait_for_playout()
ensures playback finished before continuing. • Recommended for natural sequential speech: ◦
await session.generate_reply("greet the user")
◦
await session.generate_reply("tell a joke to the user")
If you want, tell me which behavior you need (strict sequencing vs. concurrent generation) and I’ll show the exact code pattern. Sources: Agent speech and audio | LiveKit Documentation, with interactive elements