In the multi-agent mode, handoff to another agent ...
# ask-ai
g
In the multi-agent mode, handoff to another agent will additional result, I want to skip the last reply and let the new agent to handle the conversation. Is it possible: Current:
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User(say): message to trigger handoff
Agent A(say): I think I need to handoff
Agent A(logic): handoff to Agent B, reason="not my domain"
Agent B(say): hi, User, I will help you
What I want is skip the response "Agent A(say): I think I need to handoff"
t
Thanks for reaching out, Phuong. I'm an AI assistant and I'm here to help. Give me a moment while I research this topic.
""" To skip the last reply from Agent A before handing off to Agent B in a multi-agent setup, you can use the skip_next_event_if() method to conditionally skip events. Here’s a friendly little guide on how to do this: • Try using
skip_next_event_if()
to skip that last message from Agent A by checking for a
message
event with the right role:
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result.expect.skip_next_event_if(type="message", role="assistant")  # Skips the last assistant message
• If you want to skip a few messages or other events, you can chain
skip_next_event_if()
calls or simply use `skip_next()`:
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result.expect.skip_next(2)  # Skips the next two events
Feel free to reach out if you want me to walk you through this or if you have any other questions — I’m here to help! """
g
When handing off, instead of returning a new instance of Agent B, I return an already-initialized instance, is it OK?
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agent_a = AgentA()
agent_b = AgentB()
userdata.personas = {
  "Agent A": agent_a,
  "Agent B": agent_b
}

# Later when calling handoff
class AgentA(Agent):
  async def _handoff:
    return userdata.personas["Agent B"], "your call"
In this case, will the "agent_b" instance will have all chat history of "agent_a"?
t
When you hand off to an agent that’s already been initialized, the new agent will keep the chat history from the previous one only if you explicitly pass the chat_ctx parameter during the handoff. Otherwise, each new agent starts fresh without any previous conversation history. To make sure your chat history sticks around, just pass the chat_ctx from the old agent to the new one when handing off. Here’s a quick example:
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from livekit.agents import ChatContext, function_tool, Agent

class AgentA(Agent):
    @function_tool()
    async def transfer_to_agent_b(self):
        return AgentB(chat_ctx=self.session.chat_ctx)

class AgentB(Agent):
    def __init__(self, chat_ctx: ChatContext):
        super().__init__(chat_ctx=chat_ctx)
If you want me to walk you through this or help with anything else, just let me know! Sources: Workflows | LiveKit Docs | Workflows | LiveKit Docs
g
How can I use logger to log all
chat_ctx
during the
on_enter
?
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async def on_enter(self) -> None:
  self.chat_ctx # I can access the chat_ctx here
t
To log the chat_ctx during the on_enter method, you can easily use the logger to capture the chat context. Here’s a friendly little guide on how to do it:
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import logging
from livekit.agents.llm import ChatContext

logger = logging.getLogger(__name__)

async def on_enter(self) -> None:
    chat_ctx = self.chat_ctx.copy()
    <http://logger.info|logger.info>(f"Chat context on enter: {chat_ctx.to_dict()}")
    # Continue with your existing logic
    await self.update_chat_ctx(chat_ctx)
### Steps: 1. Import Necessary Components: - Bring in logging so you can use the logger. - Import ChatContext from LiveKit’s LLM module. 2. Create Logger Instance: - Set up a logger instance with a name, usually name for the current module. 3. Access and Log Chat Context: - Grab the current chat context with self.chat_ctx. - Log it using logger.info(). Converting it to a dictionary with to_dict() makes it super readable. 4. Optional: If you want to log just certain parts of the chat context, you can tweak the logging like this:
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<http://logger.info|logger.info>(f"Messages in chat context: {[msg.content for msg in chat_ctx.items if msg.type == 'message']}")
Feel free to reach out if you want me to walk you through any part of this or if you have any other questions!