Hamilton Open Source

Hey,

If I am trying to debug this function `final_result` will all the `step` functions be applied to `upstream_int` when I get it in the function body? What if it were `pipe_output`?
```@pipe_input(
    step(_add_one),
    step(_multiply, y=2),
    step(_sum, y=value(3)),
    step(_multiply, y=source("upstream_node_to_multiply")),
)
def final_result(upstream_int: int) -> int:
    pdb.set_trace()
    return upstream_int```
Slack Conversation

add_one, mulitply, sum, multiply will be applied to `upstream_int`  and in the function body that’s what you’ll get.

If it was `pipe_output`  those steps would be applied to the value returned by `final_result`.

Ok so if it were `pipe_output` then the `pipe`'d`step` s would not have yet been applied?