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Copy it there or actually create it there right-away? Shouldn't need more than

buildDir = rootProject.file("${rootBuildDir}/${name}")

. Besides that it of course will confuse anyone new to the project. 😄

Thanks - am I right that your solution will flatten the structure? (Which might not be the end of the world.) An existing plugin to copy them there is what I'm looking for, yes. I'd rather not mess with the conventions if I can avoid it.

Flatten in what sense? It would instead of

my-project/subproject1/build/foo/bar

right away create

my-project/build/subproject1/foo/bar

I think it would produce

my-project/
└── build/
    ├── subproject1/
    ├── subproject2/
    └── subproject3/

rather than

my-project/
└── build/
    ├── subproject1/
    └── project-collection/
        ├── subproject2/
        └── subproject3/

Ah, yes, that's right. But that should easily be adaptable. Something like

buildDir = rootProject.file("${rootBuildDir}/${path.replace(":", "/")}")

or similar. But as you want a copy it is anyway not what you want.

Thanks, this has given me a good enough approximation:

val rootBuildDir = buildDir

subprojects {

  val relativeProjectPath = rootProject.projectDir.toPath().relativize(this.projectDir.toPath())
  buildDir = rootProject.file("${rootBuildDir}/$relativeProjectPath")
}