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```val foo1 = objects.property&lt;String&gt;()
val foo2 = objects.property&lt;String&gt;()
val foo3 = objects.property&lt;String&gt;()
val foo4 = objects.property&lt;String&gt;()

val bar = objects.mapProperty&lt;String, String&gt;()

bar.put("foo1", foo1)
bar.put("foo2", foo2)
bar.put("foo3", foo3)
bar.put("foo4", foo4)```
?

Or do you want the providers from the extension as keys, not values?

I want them as values so this should work! I'm going to check thanks!

Besides that, if you want to combine providers lazily, what you are after is `zip(...)`.

Your first solution works! I'm going to check `zip` and see which is easier to read. Thanks you :slightly_smiling_face:

That was just general info for the future. You don't want to use `zip` here, especially as you can only `zip` two providers. So you would `zip` `foo1` with `foo2`, then `zip` the result with `foo3`, and then `zip` the result with `foo4`

Yes, I just triead and you are right, `zip`  doesn't work well for my use case. Again thank you for all the help :)