Hi, I have a scenario where I add a value to a table with multiple rows and columns. I need to iterate through the table and find the value, if its present then print its location or a success message. And if the value is not found then fail the test. How can I do this efficiently? Can someone help?

you just want to print the row index?

try something like this: cy.get('table') //selects the table .find('tr') //finds the lines .each(($row, rowIndex) => { //for each row cy.wrap($row) //select the row .find('td') //finds the cells .each(($cell, cellIndex) => { //for each cell const cellText = $cell.text() //gets cell text if (cellText.includes('value looked for')) { //if the value is found cy.log(

Value found in row ${rowIndex + 1}, column ${cellIndex + 1}

) //prints location return false //stop the loop } }) .should('not.be.empty') //make sure the line is not empty }) .should('not.be.empty') //make sure the table is not empty .should('exist') //ensures that the table exists .then(() => { //when the search is complete cy.log('Value not found') //prints error message expect(false).to.be.true //test failed })

Yes. Just the location of the element, if found. The problem I have currently is that if the element is not found, the test still passes.

- https://glebbahmutov.com/cypress-examples/recipes/find-row.html -

Thanks for this simple solution @gray-kilobyte-89541. Really appreciate it 😃